Jogo da Sueca em C

[PleaseCheese]

Estou a fazer um jogo de cartas da sueca e já consegui mostrar o baralho, "partir" e mostrar a mão de cada player o meu problema está em organizar as cartas de acordo com o naipe e a grandeza e fazer com que eles "joguem" a carta e assistam a jogada anterior.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

#define DECK_NSUITS     4
#define DECK_NVALUES    10
#define DECK_SIZE       (DECK_NSUITS * DECK_NVALUES)

#define HAND_COUNT      4
#define HAND_SIZE       (DECK_SIZE / HAND_COUNT)

#define card_suit(card) ((card >> 8) & 0xff)
#define card_value(card) (card & 0xff)
#define card_compose(suit, value) (((suit & 0xff) << 8) | (value & 0xff))
#define card_swap(card1, card2) do { if (*card1 != *card2) { *card1 ^= *card2; *card2 ^= *card1; *card1 ^= *card2; } } while (0)

void deck_build(short * deck) {
    int suit = 0, value = 0;

    for (suit = 1; suit <= DECK_NSUITS; suit++)
        for (value = 1; value <= DECK_NVALUES; value++)
            deck[(suit - 1) * DECK_NVALUES + value - 1] = card_compose(suit, value);
}

void card_output(short card) {
    switch (card_suit(card)) {
        case 1 : printf("%c", 3); break;
        case 2 : printf("%c", 4); break;
        case 3 : printf("%c", 5); break;
        case 4 : printf("%c", 6); break;
    }
    switch (card_value(card)) {
        case 1  : printf("A "); break;
        case 8 : printf("Q "); break;
        case 9 : printf("J "); break;
        case 10 : printf("K "); break;
        default : printf("%-2d", card_value(card));
    }
}

void deck_shuffle(short * deck) {
    int i = 0, r = 0;

    for (i = 0; i < DECK_SIZE; i++) {
        r = rand() % (DECK_SIZE - i);
        card_swap(&deck[r], &deck[i + r]);
    }
}


int main() {
    short deck[DECK_SIZE];
    short hands[HAND_COUNT][HAND_SIZE];
    int i, j;

    /* start randon number genereation */
    srand(time(NULL));
    
    /* deck build */
    deck_build(deck);

    /* deck destribution to the players hands */
    for (i = 0; i < HAND_COUNT; i++)
    memcpy(hands[i], &deck[i * HAND_SIZE], HAND_SIZE * sizeof(short));

    /* hand presentation */
    printf("BARALHO:\n");
    for (i = 0; i < HAND_COUNT; i++) {
        for (j = 0; j < HAND_SIZE; j++) {
            card_output(hands[i][j]);
        }
        printf("\n");
    }
    printf("\n");

    /* deck shuffle */
    deck_shuffle(deck);

    /* deck destribution to the players hands */
    for (i = 0; i < HAND_COUNT; i++)
    memcpy(hands[i], &deck[i * HAND_SIZE], HAND_SIZE * sizeof(short));

    
    /* player que baralha */
    int num = (rand() %
    (4)) + 1;
    printf("player%d baralha:\n", num);

    /* hand presentation */
    for (i = 0; i < HAND_COUNT; i++) {
        for (j = 0; j < HAND_SIZE; j++) {
            card_output(hands[i][j]);
        }
        printf("\n");
    }
   
    printf("\n");printf("\n");
    
    /* parte a hand */
    if(num == 4){
        printf("player1 parte:\n");
    }else{
        printf("player%d parte:\n", num+1);
    }
    
    for (i = 0; i < HAND_COUNT; i++) {
        for (j = 0; j < HAND_SIZE; j++) {
            card_output(hands[i][j+1]);
        }
        printf("\n");
    }

    printf("\n");printf("\n");


    /* dá a hand */
    if(num+1==4){
      printf("player1 da:\n");
    }
    else if(num+1==5){
      printf("player2 da:\n");
    }else{
        printf("player%d da:\n", num+2);
    }

    for (i = 0; i < HAND_COUNT; i++) {
        printf("player%d: ", i+1);
        for (j = 0; j < HAND_SIZE; j++) {
            card_output(hands[i][j+1]);
        }
        printf("\n");
    }
    
    return 0;
}

Uma ideia do resultado final

Também já arranjei muito código daqui mas fui alterando para o que precisava