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# Functions as Arguments ## Recommended Posts Start by repeating the code you wrote for the last section (the calculate and add functions).

Declare a variable multiply and assign to it a function declaration taking two arguments, operand1 and operand2, and which returns the result of the multiplication of the arguments.

Invoke calculate twice, passing it as a third argument the add and multiply functions respectively.

Alguém para ajudar ??

```var add = function (operand1, operand2){
return operand1 + operand2;
};
var calculate = function (operand1, operand2, operation) {
var result = operation(operand1, operand2);
console.log(result);
};
var multiply = function (operand1, operand2) {
return operand1*operand2;
};
calculate=(4,4,add);
calculate=(4,4,multiply);```

##### Share on other sites ```
var add = function (operand1, operand2){
return operand1 + operand2;
};

var multiply = function (operand1, operand2) {
return operand1*operand2;
};

var calculate = function (operand1, operand2, operation )
{
var result = operation(operand1, operand2);
return( result );
};

console.log( calculate(4,4,add) );
console.log( calculate(4,4,multiply) );```

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