Functions as Arguments

[Fernando_Diniz]

Start by repeating the code you wrote for the last section (the calculate and add functions).

Declare a variable multiply and assign to it a function declaration taking two arguments, operand1 and operand2, and which returns the result of the multiplication of the arguments.

Invoke calculate twice, passing it as a third argument the add and multiply functions respectively.

 

Alguém para ajudar ??

var add = function (operand1, operand2){
  return operand1 + operand2;
};
var calculate = function (operand1, operand2, operation) { 
  var result = operation(operand1, operand2);
console.log(result);  
};
var multiply = function (operand1, operand2) {
    return operand1*operand2;
}; 
calculate=(4,4,add);
calculate=(4,4,multiply);

 

[Zex]

var add = function (operand1, operand2){
  return operand1 + operand2;
};

var multiply = function (operand1, operand2) {
    return operand1*operand2;
}; 


var calculate = function (operand1, operand2, operation ) 
{ 
  var result = operation(operand1, operand2);
  return( result );  
};

console.log( calculate(4,4,add) );
console.log( calculate(4,4,multiply) );