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[Resolvido] Lógica - Paginação

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Boa noite, como podem ver neste exemplo aqui http://t0ze.dynip.sapo.pt/static/ tenho uma tabela com paginação, (fazendo uso de uma classe pagination).

Só que como podem ver todas as paginas são apresentadas. Já andei aqui a martelar ciclos for, mas nunca acerto... o objectivo seria:

Sendo por exemplo a pagina actual = 10 mostrar apenas

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$page = !empty($_GET['page']) ? (int)$_GET['page']: 1;
    //records per page
    $per_page = 10;
$total_count = country_count_all();
    $pagination = new pagination($page, $per_page, $total_count);
    $offset = $pagination->offset();
    $total = $pagination->total_pages();
$query ="SELECT country.*
    FROM country
    LIMIT 10
    OFFSET $offset";
$table = "";
$result_set = mysql_query($query);

$table = "<table id=\"myTable\" class=\"tablesorter\"style='width:100%; border-spacing:0;'>
	    <th>Nome Local</th>

while($country =  mysql_fetch_array($result_set)){
   $table = $table."<tr><td>".$country['Name']."</a></td>
  <td >". $country['LocalName']."</td>
echo $table;
if ($pagination->total_pages()>1) {
 if ($pagination->has_previous_page()) {
   $previouspage =   $pagination->previous_page();
   echo " <a href='index.php?page=$previouspage'> Previous </a> ";

 for ($i=1; $i <= $total; $i++) {
   if ($i == $page) {
  echo " <a href=\"index.php?page={$i}\"> <b><u>{$i}</u></b> </a>";
  echo " <a href=\"index.php?page={$i}\"> {$i} </a>";

 if ($pagination->has_next_page()) {
   $nextpage = $pagination->next_page();
   echo " <a href='index.php?page=$nextpage'> Next </a> ";

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